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Random variables $X,Y$ such that $E(X|Y)=E(Y|X)$ a.s.

Let $ X$ and $ Y$ be random variables such that $ E(|X|), E(|Y|)<\infty$ and $ E(X|Y)=E(Y|X)$ a.s. Then is it true that $ X=Y$ a.s. ? If this is not true in general, what happens if we also assume...

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WIll a proliferating 3D random walk a.s. revisit the origin?

The concept of a “proliferating random walk” on a lattice is that at any time $ t \in \Bbb N \cup 0$ , there is some set consisting of at least one particle, each of which is on its own lattice point....

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